to achieve longer zoomdistance and hopefully good resolution images, is there a factor how to multiply using 16mm optics on Super8/SuperDuper8?
As when using a Nikon F optic with adapter on the Beaulieu I calculate (x)mm times 6,3. So do anybody know what the same is for 16mm?
I tried a search but didn't find much.
Edited by David Odell, 10 July 2009 - 10:51 AM.